# Solve the 10x^2+40x-210=0 equation

10x^2+40x-210=0
a = 10; b = 40; c = -210;
Δ = b2-4ac
Δ = 402-4·10·(-210)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x1=−b−Δ√2a

x2=b+Δ2a

Δ−−√=10000−−−−−√=100

x1=bΔ2a=(40)100210=14020=7

x2=b+Δ2a=(40)+100210=6020=3